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Posted by on Tuesday, August 3, 2010 at 9:21pm.

if an engine must do 500 joules of work to pull a 10 kg load up to to a height of 4 meters ,what is the efficiency of the engine ?

  • physical science - , Tuesday, August 3, 2010 at 9:27pm

    work done: mgh=10*9.8*4

    efficiency= workdone/500j

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