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Posted by Joseph on Tuesday, August 3, 2010 at 5:21pm.

A small “coffee cup” calorimeter contains 110. g of H2O at 22.0°C. A 100. g sample of lead is heated to 90.0°C and then placed in the water. The contents of the calorimeter come to a temperature of 23.9°C What is the specific heat of lead?

[mass Pb x specific heat lead x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0.

I don't get which one is Tfinal, and Tinitial for both of them can you explain it? thank you

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