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October 30, 2014

October 30, 2014

Posted by **trigofunctions** on Tuesday, August 3, 2010 at 6:28am.

- trigo -
**Henry**, Wednesday, August 4, 2010 at 8:26pmThe 2 lines of sight represent the

hypotenuse of 2 rt. triangles, and

the height of the hill represents the vertical side of both triangles. The

hor. side of smaller triangle(d) is

measured from the bottom of hill to A.

The hor. side of the larger triangle

is = to d + 75m.

Tan30 = h/d, h = d * Tan30.

h = (d+ 75)* Tan22

- trigo -
**Henry**, Wednesday, August 4, 2010 at 8:42pmThe 2 lines of sight represent the

hypotenuse of 2 rt. triangles, and

the height of the hill represents the vertical side of both triangles. The

hor. side of smaller triangle(d) is

measured from the bottom of hill to A.

The hor. side of the larger triangle

is = to d + 75m.

Tan30 = h/d,

h = d * Tan30.

h = (d + 75)* Tan22

Substitute d * Tan30 for h.

d * Tan30 = (d + 75) * Tan22.

Solve for d:

0.5774d = (0.4040d + 30.30.

0.5774d - 0.4040d = 30.30

0.1774d = 30.30.

d = 30.30/0.1774 = 174.74m.

h = 174.74 * Tan30 = 100.9m = height

of hill.

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