posted by Kristen on .
If 20ml of glacial acetic acid (pure HC2H3O2) is diluted to 1.5L with water, what is the pH of the resulting solution. The density of glacial acetic acid is 1.08g/ml
Call acetic acid HAc.
Calculate M concd HAc.
1.08 g/mL x 1000 mL x (1 mol/molar mass HAc) = ??M HAc.
For the diluted solution,
M HAc x (20 mL/1,500 mL) = ?? M
HAc ==> H^+ + Ac^-
Ka = (H^+)Ac^-)/(HAc)
Set up an ICE chart, substitute into the Ka expression, and solve for H^+, then convert to pH.