The coordinates of the center of a circle with equation (x − 6)2 + (y + 3)2 = 72 are:
(x - h)^2 + (y - k)^2 = r^2 C(h , k) = C(6 , -3).
To find the coordinates of the center of a circle with a given equation, you need to rewrite the equation in the standard form of a circle equation: (x - h)^2 + (y - k)^2 = r^2.
In this case, the equation of the circle is (x - 6)^2 + (y + 3)^2 = 72. Comparing this with the standard form, you can see that the center coordinates are (h, k) = (6, -3).
Therefore, the coordinates of the center of the circle are (6, -3).