Posted by Crazy on Sunday, August 1, 2010 at 5:49pm.
Sin49 = h/d1 = 250m/d1.
d1 = 250/Sin49 =331.3m = Distance of 1st helicopter.
Sin37 = h/d2 = 250/d2
d2 = 250/Sin37 = 415.4m = Distance of
2nd helicopter.
d1 = r*t, t = d1/r =0.3313km / 170km
= 0.00195h = 0.00195h * 3600s/h =
7 Seconds.
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