Posted by **jan w** on Sunday, August 1, 2010 at 2:30pm.

2x+15 >= 13 and 2x-13 >= -5?

solve and graph

2x+15 >= 13

2x-13 >= -5

what's the solution x >= ?

and how does this appear on a line graph/number line?

- algebra -
**Damon**, Sunday, August 1, 2010 at 3:35pm
2x>/=-2

x >/= -1

2x>/= 8

x >/= 4

x = 4 and everything to the right of x = 4

- algebra -
**Henry**, Sunday, August 1, 2010 at 4:24pm
2X + 15 >= 13.

2X - 13 >= -5

Add the 2 Eq.

4X + 2 >= 8

Solve for X

4X >= 6

X >= 3 / 2 >= 1 1/2.

Graph the solution:

1. Draw a filled -in circle(dot) on the number line at 1 1/2. This means that X = 1 1/2 is a part of the solution.

2. Starting at the dot, draw a straight line to the right on the number line. Extend this line pass all

numbers on the right of the dot,

which means all real numbers greater

than 1 1/2 are a part of the solution.

If your inequality did not have an

equal sign (x > 1 1/2), the procedure

would have been exactly the same

except the circle would be left open

(o) meaning the 1 1/2 is not a part of

the solution. But all numbers above

1 1/2 is a part of the solution.

I hope this is helpful.

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