Posted by **samuala** on Saturday, July 31, 2010 at 11:32pm.

can someone please help me with my algebra i got this as a answer and i don't know if its right.

N(t)= -3t^3 + 23t^2 + 8t

a. Rewrite the formula by factoring the right-hand side completely.

N(t)= -3t^3 + 23t^2 + 8t

N(t)= (-t)(3t^2 - 23t - 8)

N(t)= (-t)(3t+1)(t-8)

b. Use the factored version of the formula to find N(3).

N(t)= (-t)(3t+1)(t-8)

N(3)= (-3)(3(3)+1)(3-8)

N(3)= (-3)(9+1)(-5)

N(3)= (-3)(10)(-5)

N(3)= (15)(10)

N(3)= 150

C .the workers are most efficient in about 5 and a half hours because they make almost 250 components

d. The maximum number of components assembled per hour during a 8 hour shift is 1115 components.

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