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July 23, 2014

July 23, 2014

Posted by **Mely** on Saturday, July 31, 2010 at 9:51pm.

- calculus -
**drwls**, Sunday, August 1, 2010 at 6:45amLet x be the length of the side of the square taken off each corner. The open box will have length 56-2x, width 21-2x and height x.

The volume of the box is

V(x) = x(56-2x)(21-2x)

Set the derivative dV/dx equal to zero and compute the corresponding x. Use that to compute the maximum volume.

Someone will gladly critique your work if you show what you did and need additional assistance.

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