Posted by Jennifer on Saturday, July 31, 2010 at 9:00pm.
Essentials of statistics is the subject and the question is: The population of IQ scores forms a normal distribution with a mean of u=100 and a standard deviation of sigma=15. What is the probability of obtaining a sample mean greater than M=105 for a random sample of n=36 people? What is the formula in simple terms.

Statistics  Ms. Sue, Saturday, July 31, 2010 at 9:13pm
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Statistics  PsyDAG, Sunday, August 1, 2010 at 12:04pm
Z = (mean1  mean2)/standard error (SE) of difference between means
SEdiff = √(SEmean1^2 + SEmean2^2)
SEm = SD/√(n1)
Since only one SD is provided, you can use just that to determine SEdiff.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion corresponding the the Z score.
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