Three identical charges (q = +5.0mC) are along a circle with radius of 2.0m at angles of 30, 150, and 270 degrees. What is the the resultant electric field at the center?
I WONA TO BE THE QUESTION ANSWER
I WANT TO BE THE ANSWERS OF FOR THISE QUESTION
The charges are symettrical at the center, wouldn't they add to zero? So E at the center would be the vector sum of all the contributions, so it is zero.
answ
PLEASE ANSWER THE QUESTION
PLEASE HELP AMANUEL
To find the resultant electric field at the center, we need to calculate the electric field created by each charge and then add them vectorially.
Let's start by calculating the electric field created by a single charge at the center. The electric field at a distance r from a point charge q can be calculated using Coulomb's Law:
E = k * (q / r^2)
where:
E is the electric field
k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2)
q is the charge
r is the distance from the charge
Since the charges are identical, we can simplify calculations by calculating the electric field created by one charge and then multiplying it by 3 (since there are three charges).
For each charge, the distance from the center is the radius of the circle (r = 2.0m).
Therefore, for each charge:
E = (8.99 x 10^9 Nm^2/C^2) * [(5.0 x 10^-3 C) / (2.0m)^2]
Now let's calculate the electric field for each charge:
q1 (30 degrees):
E1 = (8.99 x 10^9 Nm^2/C^2) * [(5.0 x 10^-3 C) / (2.0m)^2]
q2 (150 degrees):
E2 = (8.99 x 10^9 Nm^2/C^2) * [(5.0 x 10^-3 C) / (2.0m)^2]
q3 (270 degrees):
E3 = (8.99 x 10^9 Nm^2/C^2) * [(5.0 x 10^-3 C) / (2.0m)^2]
Finally, to find the resultant electric field at the center, we need to add the electric fields created by each charge. Since the charges are evenly distributed on a circle, we can treat them as vectors and use vector addition:
E_total = E1 + E2 + E3
Calculate E_total by summing the electric field values obtained earlier.