Post a New Question

math-word problem

posted by .

The width of a rectangle is fixed at 21cm. What lengths will make the perimeter greater than 80cm.

Please help with this word problem I do not even know where to begin.

  • math-word problem -

    The perimeter is the distance around the rectangle.

    P = 2L + 2W

    Two widths = 42 cm.

    80 - 42 = 38

    38/2 = 19

    The length must be over 19 cm.

  • math-word problem -

    The shadow of a 4 foot pole is 6 feet long at the same time the shadow of a tower is 52.5 feet long. How tall is the tower?

  • math-word problem -

    Please help me I am studying for an exam.
    Typist x can type 20 forms per hour and typist y can typev30 forms a nor. How will it take 1 and 2 to type 30 forms?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question