The width of a rectangle is fixed at 21cm. What lengths will make the perimeter greater than 80cm.
Please help with this word problem I do not even know where to begin.
The perimeter is the distance around the rectangle.
P = 2L + 2W
Two widths = 42 cm.
80 - 42 = 38
38/2 = 19
The length must be over 19 cm.
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Please help me I am studying for an exam.
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To solve this word problem, we need to understand the concepts of perimeter and how it relates to the length and width of a rectangle.
The perimeter of a rectangle is the sum of all its sides. In this case, we are given that the width of the rectangle is fixed at 21cm. Let's assume the length of the rectangle is 'L' cm.
The formula for calculating the perimeter of a rectangle is:
Perimeter = 2(length + width)
Given that the width is fixed at 21cm, the formula can be written as:
Perimeter = 2(L + 21)
We are asked to find the lengths that will make the perimeter greater than 80cm. So we can set up an equation:
2(L + 21) > 80
Now, let's solve this inequality to find the acceptable lengths:
First, distribute the 2 on the left side of the equation:
2L + 42 > 80
Next, subtract 42 from both sides:
2L > 80 - 42
Simplifying the right side:
2L > 38
Lastly, divide both sides of the equation by 2 to isolate L:
L > 38 / 2
L > 19
Therefore, any length greater than 19cm will make the perimeter greater than 80cm.