Posted by **Michelle** on Saturday, July 31, 2010 at 4:18pm.

The width of a rectangle is fixed at 21cm. What lengths will make the perimeter greater than 80cm.

Please help with this word problem I do not even know where to begin.

- math-word problem -
**Ms. Sue**, Saturday, July 31, 2010 at 4:22pm
The perimeter is the distance around the rectangle.

P = 2L + 2W

Two widths = 42 cm.

80 - 42 = 38

38/2 = 19

The length must be over 19 cm.

- math-word problem -
**Joshua**, Monday, October 1, 2012 at 6:21pm
The shadow of a 4 foot pole is 6 feet long at the same time the shadow of a tower is 52.5 feet long. How tall is the tower?

- math-word problem -
**linda**, Tuesday, March 12, 2013 at 10:57pm
Please help me I am studying for an exam.

Typist x can type 20 forms per hour and typist y can typev30 forms a nor. How will it take 1 and 2 to type 30 forms?

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