Saturday

August 30, 2014

August 30, 2014

Posted by **cyn** on Saturday, July 31, 2010 at 2:45pm.

- college algebra -
**bobpursley**, Saturday, July 31, 2010 at 6:23pmN(x)=-.4( x^2 -30 x -25)

N(x)=-.4( x^2-30x+225-250)

N(x)=-.4( x-15)^2 +.4(250)

so the maximum is at x=15

You solve for N(15).

Also, I recommend you graph this on your graphing calc, to see if it is correct.

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