Posted by cyn on Saturday, July 31, 2010 at 2:45pm.
N(x)=-.4( x^2 -30 x -25)
N(x)=-.4( x^2-30x+225-250)
N(x)=-.4( x-15)^2 +.4(250)
so the maximum is at x=15
You solve for N(15).
Also, I recommend you graph this on your graphing calc, to see if it is correct.
Related Questions
College Algebra 2 - The number of tickets sold each day for an upcoming ...
Algebra 2 - The number of tickets sold each day for an upcoming performance of ...
algebra - The number of tickets sold each day for an upcoming performance of ...
college - how can i solve this problem? The number of tickets sold each day for ...
math - The number of tickets sold each day for an upcoming performance of Hanel...
Math/Algebra - The number of tickets sold each day for an upcoming performance ...
algebra - The number of tickets soldeach day for an upcoming performance of ...
algebra - The number of tickets sold each day for upcoming perfomance of Handel...
Math - The number of tickets sold each day for an upcoming performance is given ...
math - the number of tickets for an upcoming concert is given by N(x)=-0.5x^2+...
For Further Reading