Posted by leanne on Friday, July 30, 2010 at 11:31pm.
solve 1tan^2x=0 , 0≤x≤2pi

grade 12 math  Reiny, Saturday, July 31, 2010 at 7:21am
1tan^2x=0
tan^2 x = 1
tan x = ±1
x = π/4, π  π/4, π + π/4, or 2π  π/4
x π/4, 3π/4, 5π/4, 7π/4
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