Posted by **leanne** on Friday, July 30, 2010 at 11:31pm.

solve 1-tan^2x=0 , 0≤x≤2pi

- grade 12 math -
**Reiny**, Saturday, July 31, 2010 at 7:21am
1-tan^2x=0

tan^2 x = 1

tan x = ±1

x = π/4, π - π/4, π + π/4, or 2π - π/4

x π/4, 3π/4, 5π/4, 7π/4

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