determine the inverse of y=2(3)^x+1
x= 2*3^y +1
(1/2)(x-1)=3^y
take the log of each side
log (1/2)+log(x-1)=ylog3
y= (log 1/2 + log(x-1)/log3
(1/2)(x-1)=3^y
take the log of each side
log (1/2)+log(x-1)=ylog3
y= (log 1/2 + log(x-1)/log3