Please help with this question. A bag contains 10 marbles of which 3 are red. A marble is selected at random and replaced. A second marble is then selected at random. What is the probability that both marbles are red?
3/10 * 3/10 = .3 * .3 = ?
Sorry probability is not really easy for me. I was thinking .3=9
To find the probability that both marbles drawn from the bag are red, we need to calculate the probability of two independent events happening consecutively. Here are the steps to solve this:
Step 1: Determine the probability of drawing a red marble in the first selection.
Given that there are 10 marbles in total and 3 red marbles, the probability of selecting a red marble on the first draw is 3/10.
Step 2: Since the marble is replaced after each draw, the probability remains the same for the second selection.
Therefore, the probability of drawing a red marble in the second selection is also 3/10.
Step 3: Multiply the probabilities from Step 1 and Step 2 to find the joint probability.
To find the probability of two independent events happening consecutively, multiply their individual probabilities together:
(3/10) * (3/10) = 9/100
So, the probability that both marbles drawn are red is 9/100 or 0.09 (9%).