Tuesday

December 1, 2015
Posted by **donna** on Friday, July 30, 2010 at 9:35pm.

I know its not 6,760,000

- college -
**bobpursley**, Friday, July 30, 2010 at 10:22pmconsider the Pr of two letters the same: 1/26

Now consider the Pr of two numbers: 1/10*9/10*8/10

Now the Pr of three numbers the same:

1/10*1/10*9/10

now the Pr of four numbers the same:

1/10*1/10*1/10

now the pr of having two pairs of numbers the same:

1/10*9/10*1/9

Pr(at least one letter or digit repeated:

sum of (two letters, no numbers) + (two letters, two numbers)+(two letters, three numbers)+(two letters, four numbers)+(two letters, two pairs of numbers) + (no letters, two numbers)+(no letters, threenumbers)+(no letters, four numbers)+ (no letters,two pairs of numbers)

I will do the first four probabilities for you:

Pr(twoletters, no numbers)=1/26*9/10*8/10*7/10

Pr(two letters, two numbers)=1/26*1/10*9/10*8/10

Pr(two letters, three numbers)=1/26*1/10*1/10*9/10

See if you can finish.

- college -
**Anonymous**, Saturday, July 31, 2010 at 4:48am,ll

- college -
**Ashlee**, Monday, August 6, 2012 at 10:43pmYour asking for how many combinations and not the probability so ignore the answer above.

First find the number of combinations if all letters and numbers can be repeated

(26*26*10*10*10*10)=6760000

Then find the number of combinations if none were repeated

(26*25*10*9*8*7)=3276000

(value of combinations that can be repeated)-(value of combinations that no letter or number could be repeated) = 6760000-3276000= 3484000