A basketball player shoots free throws and makes them with probability 1/3. What is the probability the player will miss three in a row?
The answer is 8/27 attempts, but I'm not sure how this answer was obtained. Any thoughts?
To find the probability that the player will miss three free throws in a row, we need to multiply the probabilities of each individual miss.
The probability of missing a free throw is 1 - probability of making a free throw, which is 1 - 1/3 = 2/3.
Since each free throw is independent of the others, we can multiply the probabilities together:
P(miss three in a row) = (2/3) * (2/3) * (2/3) = 8/27.
Therefore, the probability that the player will miss three free throws in a row is 8/27.
To calculate the probability that the player will miss three free throws in a row, we need to multiply the probability of missing a single free throw by itself three times.
The probability of missing a single free throw is given as 1/3. So, the probability of missing three in a row will be (1/3) * (1/3) * (1/3) = 1/27.
Therefore, the probability that the player will miss three free throws in a row is 1/27.