The preimeter of a retangle is 98. The length is 7m more than twice the width. Fid the dimension?
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L = 2W + 7
2L + 2W = 98
2(2W + 7) + 2W = 98
Solve last equation for W, then insert value into first equation to find L. Check by putting both values into the second equation.
To find the dimensions of the rectangle, we'll set up a system of equations.
Let's assume the width of the rectangle is 'w' meters.
According to the given information, the length of the rectangle is 7 meters more than twice the width, which can be expressed as: length = 2w + 7.
The perimeter of a rectangle is twice the sum of its length and width. We can use this information to form our equation:
Perimeter = 2(length + width)
98 = 2(2w + 7 + w)
Simplifying the equation:
98 = 2(3w + 7)
98 = 6w + 14
6w = 98 - 14
6w = 84
w = 84 / 6
w = 14
So, the width of the rectangle is 14 meters.
To find the length, we'll substitute the value of the width into the expression for the length:
Length = 2w + 7
Length = 2(14) + 7
Length = 28 + 7
Length = 35
Therefore, the dimensions of the rectangle are width = 14 meters and length = 35 meters.