Posted by joy on Thursday, July 29, 2010 at 10:42am.
By trial and error, I found that three numbers meet the first criteria: 88, 79, 97.
Which of those numbers meets the second criteria?
79
79
Let A = the first digit and B + the second digit.
Then A + B = 16 and 10B + A = 10A + B + 18 or B - A = 2
Adding A + B = 16 and B - A = 2 yields B = 9 and A = 7 making the initial number 79.
Therefore, A + B = 16 and 97 - 79 = 17.
Sorry for the mental error. The hand was slower than the eye.
Let A = the first digit and B + the second digit.
Then A + B = 16 and 10B + A = 10A + B + 18 or B - A = 2
Adding A + B = 16 and B - A = 2 yields B = 9 and A = 7 making the initial number 79.
Therefore, A + B = 16 and 97 - 79 = 18
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