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March 26, 2017

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A 1000kg load is suspended from the end of a horizontal boom. The boom is supported by a cable that makes an angle of 35deg with the boom.

a) what is the tension in the cable?
b) what is the horizontal force on the boom?

  • Resolution of vectors - ,

    1000*9.8 = 9800 Newtons weight
    Force up from cable = T sin 35
    force up from cable = weight down
    T sin 35 = 9800

  • Resolution of vectors - ,

    Force inward from tension = T cos 35
    = 9800 cos 35/sin 35
    which is the horizontal compression force on the boom.

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