# Algebra

posted by
**michelle**
.

Square lot. Sam has a lot that he thought was a square, 200 feet by 200 feet. When he had it surveyed, he discovered that one side was x feet longer than he thought and that the other side was x feet shorter than he thought.

a).

Find a polynomial A(x) that represents the new area.

b).

Find A(2)

c).

If x=2 feet then how much less area does he have than he thought he had?

Answer:

a).

A(x)=(200-x)*(200+x)

A(x)=40,000-x^2

b).

A(2)=40,000-(2)^2

A(2)=40,000-4

A(2)=39,996 feet^2

c).

Initial area= 200*200=40,000 feet^2

Present area A(2)=39,996 feet^2

40,000 – 39,996= 4 feet ^2

I need to know if i done this correctly.