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August 1, 2014

August 1, 2014

Posted by **Anonymous** on Wednesday, July 28, 2010 at 11:09am.

(a) an axis that passes through point P and is perpendicular to the plane of the figure, and

(b) an axis that passes through point P, is perpendicular to the rod of length 2L, and lies in the plane of the figure.

The figure shows a point P, then to the left of that point is a ball of mass 2M connected by a rod length L at an angle theta degrees from the horizontal. There is another mass 2M ball that is connected by a rod of length L at negative theta to the horizontal. To the right of point P there is a ball of mass M connected by a rod of length 2L.

So far, I have the formula K-.5Iw2, but I dont know how to find I for this system of particles. Any help would be much appreciated

- Physics -
**bobpursley**, Wednesday, July 28, 2010 at 11:24amThe system moment of inertia will be the sum of all three. If the masses are the same, and the lengths the same, 3/2mr^2 will be total. Remember, when you derived the moment of inertia, you integrated (summed) all point masses at some distance r from the rotation.

- Physics -
**Anonymous**, Wednesday, July 28, 2010 at 9:56pmOkay so I got the first part alright, but then when the axis of rotation changes, would that affect I?

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