Tuesday
October 21, 2014

Homework Help: chemistry

Posted by Kat on Wednesday, July 28, 2010 at 12:06am.

Calculate [acetate] of 0.057 mol/L solution of acetic acid of Ka = 1.76x10^-5

i know to find Ka it's:
Ka= products/reactants
so i tried doing an ICE table with the equation to be:
CH3CO2 + H2O <--> CH3COOH + H
am i on the right track? if not...help please!

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