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December 20, 2014

December 20, 2014

Posted by **sha** on Tuesday, July 27, 2010 at 12:12pm.

- math -
**Reiny**, Tuesday, July 27, 2010 at 12:18pmIf F and E are independent events then P(E and F) = 0

and we also know

P(E or F) = P(E) + P(F) - P(E and F)

.3 = .2 + P(F) - 0

P(F) = .1

- math -
**David**, Tuesday, July 27, 2010 at 2:49pmLet P(F)= X

since E and F are independent eveents,

P(EnF)= P(E)* P(F)

therefore, P(EnF)= 0.2X

but P(EuF)=P(E)+ P(F)- P(EnF)

0.3= 0.2 + x - 0.2x

x = 1/8

- math -
**David**, Tuesday, July 27, 2010 at 2:56pmsorry, i made a mistake, for mutually exculsive events, P(EnF)= 0, hence,

from the previous equation,

0.3=0.2+P(F)-0

so P(F)= 0.1

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