Friday

August 29, 2014

August 29, 2014

Posted by **Praveen** on Tuesday, July 27, 2010 at 9:02am.

- 11th Grade Physics -
**bobpursley**, Tuesday, July 27, 2010 at 9:24ambreak the problem into three parts:

accelerating, constant speed, deaccelerating.

Let x be the accelerating distance, y be the constant speed distance, x/4 be the deaccelerating distance.

1000=x+y+x/4 or 5x/4 +y=1000, or y= 1000-5x/4

so solve for x first. 72km/hr = 20m/s

Vf^2=2ad

400=2*1*x or x=200 that leads to all the other distances.

time= sum of distances divided by avg velocity during that time.

time=200/10 +750/20 +50/10

check my work.

- 11th Grade Physics -
**Praveen**, Wednesday, July 28, 2010 at 2:58pmThe answer to this question is 62.5s. Can you please explain it properly what is that Vf^2 = 2ad

**Related Questions**

11th grade - An automobile with an initial speed of 4.56m/s accelerates ...

11th phyics - An automobile with an initial speed of 4.56 m/s accelerates ...

physics, HELP ASAP PLEASE! - a car starts and accelerates uniformly at a rate of...

Physics - A bus starts from rest at a bus stop and accelerates at a rate of 1.12...

Physichs - A pedestrian is running at his maximum speed of 6.0m/s to catch a ...

11th grade - An automobile with an initial speed of 4.56 m/s accelerates ...

Physics - An automobile with an initial speed of 3.56 m/s accelerates uniformly ...

physics - Between two stations a train acclerates uniformly at first, then moves...

physics - An automobile with an initial speed of 6.60 m/s accelerates uniformly ...

physics - An automobile with an initial speed of 6.60 m/s accelerates uniformly ...