math116
posted by trudy on .
I really need help i am so stuck i can not figure this out we are trying to find the slopes here is an example of what i am doing
i get everything all theway till a certain point
example: (4,9);2x=5y+6
the answer is 2/5x+53/5 but i don't know how they came up with 53 that is where I am getting stuckwhat are they doing to come up with that

Trudy, based on the answer you gave;
you want to find the Eq of a line that
passes through the given point with a
slope = to the given Eq.
Given: (4 , 9) ,2X = 5Y + 6.
2X  5Y = 6, Slope = A / B = 2 /5
2 / 5
Y = mX + B
Plug in the gtven point to find b:
9 = 2 / 5(4) + b
solve for b:
b = 9 + 8 / 5, 9 = 45 / 5, therefore
b = 45 / 5 + 8 / 5 = 53 / 5.
Eq: Y = 2/5X + 53 / 5 
how did you come up with b=9+8/5,9=45/5
you lost me there help i have five to do like this and i really am trying to under stand it 
9 = 2/5 (4) + b
9 = 8/5 + b
add 8/5 to each side of Eq
8/5 + 9 = 8/5  8/5 + b
8/5 +9 = b
To add 8/5 and 9 , they should have
a common denominator which is 5.
8/5 +45/5 = b
53/5 = b, or b = 53/5
Trudy, you are having problems
with solving basic Eq and fractions.