Posted by **trudy** on Monday, July 26, 2010 at 1:55pm.

I really need help i am so stuck i can not figure this out we are trying to find the slopes here is an example of what i am doing

i get everything all theway till a certain point

example: (-4,9);2x=5y+6

the answer is 2/5x+53/5 but i don't know how they came up with 53 that is where I am getting stuckwhat are they doing to come up with that

- math116 -
**Henry**, Monday, July 26, 2010 at 6:10pm
Trudy, based on the answer you gave;

you want to find the Eq of a line that

passes through the given point with a

slope = to the given Eq.

Given: (-4 , 9) ,2X = 5Y + 6.

2X - 5Y = 6, Slope = -A / B = -2 /-5

2 / 5

Y = mX + B

Plug in the gtven point to find b:

9 = 2 / 5(-4) + b

solve for b:

b = 9 + 8 / 5, 9 = 45 / 5, therefore

b = 45 / 5 + 8 / 5 = 53 / 5.

Eq: Y = 2/5X + 53 / 5

- math116 -
**trudy**, Monday, July 26, 2010 at 7:32pm
how did you come up with b=9+8/5,9=45/5

you lost me there help i have five to do like this and i really am trying to under stand it

- math116 -
**Henry**, Monday, July 26, 2010 at 10:57pm
9 = 2/5 (-4) + b

9 = -8/5 + b

add 8/5 to each side of Eq

8/5 + 9 = 8/5 - 8/5 + b

8/5 +9 = b

To add 8/5 and 9 , they should have

a common denominator which is 5.

8/5 +45/5 = b

53/5 = b, or b = 53/5

Trudy, you are having problems

with solving basic Eq and fractions.

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