Posted by trudy on Monday, July 26, 2010 at 1:55pm.
Trudy, based on the answer you gave;
you want to find the Eq of a line that
passes through the given point with a
slope = to the given Eq.
Given: (-4 , 9) ,2X = 5Y + 6.
2X - 5Y = 6, Slope = -A / B = -2 /-5
2 / 5
Y = mX + B
Plug in the gtven point to find b:
9 = 2 / 5(-4) + b
solve for b:
b = 9 + 8 / 5, 9 = 45 / 5, therefore
b = 45 / 5 + 8 / 5 = 53 / 5.
Eq: Y = 2/5X + 53 / 5
how did you come up with b=9+8/5,9=45/5
you lost me there help i have five to do like this and i really am trying to under stand it
9 = 2/5 (-4) + b
9 = -8/5 + b
add 8/5 to each side of Eq
8/5 + 9 = 8/5 - 8/5 + b
8/5 +9 = b
To add 8/5 and 9 , they should have
a common denominator which is 5.
8/5 +45/5 = b
53/5 = b, or b = 53/5
Trudy, you are having problems
with solving basic Eq and fractions.
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