Vincent decided to beat his friend's average velocity of 4 m/s. What is the shortest amount of time to beat his friend's recordin a displacent of 20 meters? *SHOW ALL WORK AND EXPLAIN THOROUGHLY*
I will be happy to critique your thinking.
velocity = displacement/time
4m/s = 20/time
20/4 = 5s
so any time less than 5 seconds is enough to beat vincent.
I think that's the answer..
To find the shortest amount of time to beat his friend's average velocity, we need to determine Vincent's velocity and then use it to calculate the time taken to cover a displacement of 20 meters.
Velocity is defined as the displacement over a given time. In this case, Vincent wants to determine the time it takes to cover a displacement of 20 meters.
Let's assume Vincent's average velocity is V m/s. We need to find the value of V such that it is greater than his friend's average velocity of 4 m/s. This will ensure that Vincent beats his friend's record.
Since velocity is equal to displacement divided by time, we have the equation:
V = 20 meters / t
where t is the time taken in seconds.
Rearranging the equation to solve for t, we get:
t = 20 meters / V
To beat his friend's record, Vincent needs to have a velocity greater than 4 m/s. Therefore, V > 4 m/s.
Now, to find the shortest time, we need to find the smallest possible value of V that satisfies the condition V > 4 m/s. The smallest value would be the minimum allowed value above 4 m/s.
Let's assume V = 4.01 m/s. Substituting this value into the equation, we can calculate the corresponding time:
t = 20 meters / 4.01 m/s = 4.988 seconds
So, with an average velocity of 4.01 m/s, Vincent can beat his friend's record in approximately 4.988 seconds.
It's important to note that this is the shortest amount of time to beat his friend's record only if Vincent's velocity is exactly equal to 4.01 m/s. If Vincent's velocity is greater than 4.01 m/s, the time taken to cover the displacement of 20 meters will be shorter.