February 25, 2017

Homework Help: Calc I

Posted by Kate on Saturday, July 24, 2010 at 3:48pm.

y = (x^2 -4)/(x^2 - x -12)

dy/dx of numerator I got 2x
dy/dx of denomenator I got 2x - 1
dy/dx of y I got (x^2 - 16x -4)/((x-4)^2(x+3)^2)

setting numerator to zero and solving got 8 +/- sqrt(65) with the critical value being the +
setting denomenator to zero and solving got 4 and -3 which are both out of range of the original function...

so now what how do I find the range kind of confused... found one critical value how do I find the others kind of lost here thanks

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions