4Al + 3O2 ---> 2Al2O3
How many moles of Al2O3 are produced when 4.33 moles of Al are reacted?
Use the coefficients in the balanced equation.
4.33 mols Al x (2 moles Al2O3/4 moles Al) = ??
0.5
The balanced chemical equation for the reaction is:
4Al + 3O2 ---> 2Al2O3
From the equation, we can see that 4 moles of aluminum (Al) react to produce 2 moles of aluminum oxide (Al2O3).
Therefore, the ratio of Al to Al2O3 is 4:2, which simplifies to 2:1.
To determine the number of moles of Al2O3 produced when 4.33 moles of Al are reacted, we can set up a proportion:
(4 moles Al / 2 moles Al2O3) = (4.33 moles Al / x moles Al2O3)
Cross multiplying and solving for x, we get:
4 * x = 2 * 4.33
4x = 8.66
x = 8.66 / 4
x ≈ 2.165
Therefore, approximately 2.165 moles of Al2O3 are produced when 4.33 moles of Al are reacted.
To find the number of moles of Al2O3 produced when 4.33 moles of Al are reacted, we need to use the balanced chemical equation given:
4Al + 3O2 ---> 2Al2O3
From the equation, we can see that the molar ratio between Al and Al2O3 is 4:2, which can be simplified to 2:1. This means that for every 2 moles of Al, 1 mole of Al2O3 is produced.
Now, we can set up a simple proportion to find the number of moles of Al2O3:
2 moles of Al -> 1 mole of Al2O3
4.33 moles of Al -> x moles of Al2O3
Using the proportion:
(4.33 moles of Al) * (1 mole of Al2O3 / 2 moles of Al) = 2.165 moles of Al2O3
Therefore, when 4.33 moles of Al are reacted, 2.165 moles of Al2O3 are produced.