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March 26, 2017

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What are the steps to graphing this quadratic equation? Y=(-2x)^2

  • Graphing - ,

    It is a parabola U. See what happens with the y's when you use 0, +1, and -1 for the x's.

  • Graphing - ,

    Y = (-2X)^2 = 4X^2.

    1. Calculate coordinates of the vertex:
    h = Xv = -b / 2a = o/8 = 0.
    K = Yv = 4(0)^2 = 0. So the vertex is
    at the origin. V(h.k) = (0 , 0).

    2. Select values of X on both sides
    of vertex and cal. the corresponding
    value of Y using the given Eq.
    (-2 , 16) , (-1 , 4) , (0 , 0) ,
    (1 , 4) , (2 , 16).

    The graph should show a Y-parabola
    that opens upward with vertex at the
    origin.

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