Posted by **AJ** on Friday, July 23, 2010 at 10:48am.

Given the function f(x) = 1/(sqrt x)

a. Does f(x) exist at x=0?

b. Does f'(x) exist at x=0?

c. Explain why integral (from 0->1) f(x)dx does exist.

THANK YOU.

- Math (easy question) -
**bobpursley**, Friday, July 23, 2010 at 11:38am
a) no, one is not allowed to have zero in the denominator.

b. f(x)=1/sqrt(x)

f'= -1/(2 x^{-3/2}) yes it exists

c. if an endpoint does not exist, one cannot integrate it.

- Math (easy question) -
**AJ**, Friday, July 23, 2010 at 11:51am
Thank you so much! but are you sure for part c.?

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