Posted by AJ on .
Given the function f(x) = 1/(sqrt x)
a. Does f(x) exist at x=0?
b. Does f'(x) exist at x=0?
c. Explain why integral (from 0>1) f(x)dx does exist.
THANK YOU.

Math (easy question) 
bobpursley,
a) no, one is not allowed to have zero in the denominator.
b. f(x)=1/sqrt(x)
f'= 1/(2 x^{3/2}) yes it exists
c. if an endpoint does not exist, one cannot integrate it. 
Math (easy question) 
AJ,
Thank you so much! but are you sure for part c.?