Posted by AJ on Friday, July 23, 2010 at 10:48am.
Given the function f(x) = 1/(sqrt x)
a. Does f(x) exist at x=0?
b. Does f'(x) exist at x=0?
c. Explain why integral (from 0>1) f(x)dx does exist.
THANK YOU.

Math (easy question)  bobpursley, Friday, July 23, 2010 at 11:38am
a) no, one is not allowed to have zero in the denominator.
b. f(x)=1/sqrt(x)
f'= 1/(2 x^{3/2}) yes it exists
c. if an endpoint does not exist, one cannot integrate it.

Math (easy question)  AJ, Friday, July 23, 2010 at 11:51am
Thank you so much! but are you sure for part c.?
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