The specific heat capacity of steel is 445 Jkg K.
How much energy is required to raise the temperature of a 0.410g of kettle
which contains 1.2L of water from 20 degrees Celsius to boiling point?
Add the heat to increase both the steel and the water to the final temp.
I will be happy to critique your thinking or work.
First you have to know the formulas need
substitude the formulas with the given information
and solve
To calculate the energy required to raise the temperature of the kettle, we first need to determine the mass of the kettle. Given that the specific heat capacity of steel is 445 J/kg K and the mass of the kettle is 0.410g, we need to convert the mass to kilograms by dividing by 1000:
Mass of the kettle = 0.410g / 1000 = 0.00041 kg
Now we can calculate the energy required using the specific heat formula:
Energy = mass * specific heat capacity * change in temperature
Let's break down the calculation step by step.
1. Calculate the change in temperature:
The kettle needs to be heated from 20 degrees Celsius to boiling point. The boiling point of water is 100 degrees Celsius, so the change in temperature is:
Change in temperature = 100°C - 20°C = 80°C
Note: Remember to always convert temperature to Kelvin for the specific heat formula by adding 273.15. So, the change in temperature in Kelvin is:
Change in temperature = 80°C + 273.15 = 353.15 K
2. Calculate the energy required:
Energy = mass * specific heat capacity * change in temperature
Energy = 0.00041 kg * 445 J/kg K * 353.15 K
Now, multiply the three values together:
Energy = 0.00041 kg * 445 J/kg K * 353.15 K
Calculating this equation will give you the amount of energy required to raise the temperature of the kettle from 20 degrees Celsius to boiling point in joules (J).