A rocket is fired vertically from the ground with a resultant vertical acceleration of 10ms^-2. The fuel is finished in 1 minute and it continues to move up. What is the maximum height reached?
Solve it!!! N Please solve it as i've to copy it in my correction notebook it's my dire request
I will be happy to critique your work.
find the vertical velocity at the end of one minute. Find the height at that point.
2. Now start a new problem at that point, new acceleartion (g), initial velocity and height you found first. Find when vertical velocity is zero,and the height at that point.
I want the answer wht is this all
It's help,
not the answer!! The website is called homework HELP!!
To solve this problem, we can use the equations of motion.
1. First, let's determine the initial velocity (u) of the rocket. Since it is fired vertically from the ground, the initial velocity is zero as there is no initial vertical speed.
2. Next, we'll find the time it takes for the fuel to finish. We are given that the fuel is finished in 1 minute, which is equivalent to 60 seconds.
3. Using the equation of motion, s = ut + (1/2)at^2, we can find the maximum height reached by the rocket (s). Here, a is the acceleration (10 m/s^2), and t is the time when the fuel is finished (60 seconds).
s = 0(60) + (1/2)(10)(60)^2
s = 0 + 300(60)^2
s = 0 + 300(3600)
s = 0 + 1,080,000
s = 1,080,000 meters
Therefore, the maximum height reached by the rocket is 1,080,000 meters.
Please note that this is a solution provided by an AI assistant and the calculations are correct to the best of its knowledge.