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October 1, 2014

October 1, 2014

Posted by **Sonia** on Wednesday, July 21, 2010 at 10:02pm.

- Trig -
**Reiny**, Wednesday, July 21, 2010 at 10:41pmThe hardest part is drawing the diagram.

I have AB at 45° and length 11

point S (for sailor) is to the right, slightly below A so that angle ASB = 48°.

angle B = 12° and angle A = 120°

( I got this by drawing NS-EW lines at A, at B and at S, then using your bearings and properties of parallel lines)

so we have a/sin12 = 11/sin48

a = 3.08

and

b/sin120 = 11/sin48

b = 12.82

for the shortest distance to the shore we have to assume the the shore continues along the line of AB.

We have a nice right-angled triangle where

sin 60 = x/3.08

x = 2.67

your answers are clearly rounded off

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