Posted by **Kate** on Wednesday, July 21, 2010 at 7:52pm.

Did I do these probelms correctly?

Find the intercepts

1. y^2 = x^2 - 4x

y^2 = x(x - 4)

Y intercepts

y^2 = 0(0 - 4)

(0,0)

x intercepts

0 = x(x - 4)

0 = x - 4

4 = x

(4,0)

2. y = (x (x + 3))/(3x + 1)^2

y intercetps

y = (0(0 + 3))/(3(0) +1)^2

y = 3/1

(0,3)

x intercepts

0 = (x (x + 3))/(3x + 1)^2

0 = x(x + 3)

-3 = x

(-3,0)

- Algebra I -
**Reiny**, Wednesday, July 21, 2010 at 10:52pm
correct, except in your last part ...

0 = x(x + 3)

so x = 0 or x = -3

so you have 2 x intercepts, (0,0) and (-3,0)

you only had one of those.

## Answer this Question

## Related Questions

- Algebra - Did I do this right? Find the vertex, the x intercepts and y ...
- algebra - How do you find any x-intercepts and y-intercepts. If no x-intercepts ...
- Math - x-intercepts and y-intercepts - Hi, can someone help me with intercepts. ...
- algebra - want to know if this right find the x and y intercepts of the equation...
- Math - If a graph of a quadratic function can have 0, 1 or 2 x-intercepts. How ...
- quadratic functions - The graph of a quadratic function can have 0, 1 or 2 x-...
- Algebra - Find the x and y intercepts and graph the equation plotting the ...
- algebra - Graphing Quadratic Functions Find any x-intercepts and the y-intercept...
- algebra - Suppose that a quadratic equation had two x-intercepts. How could you ...
- algebra - -2x+5y=-15 Find the x- and y-intercepts and graph the equation ...

More Related Questions