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December 18, 2014

December 18, 2014

Posted by **Kate** on Wednesday, July 21, 2010 at 7:52pm.

Find the intercepts

1. y^2 = x^2 - 4x

y^2 = x(x - 4)

Y intercepts

y^2 = 0(0 - 4)

(0,0)

x intercepts

0 = x(x - 4)

0 = x - 4

4 = x

(4,0)

2. y = (x (x + 3))/(3x + 1)^2

y intercetps

y = (0(0 + 3))/(3(0) +1)^2

y = 3/1

(0,3)

x intercepts

0 = (x (x + 3))/(3x + 1)^2

0 = x(x + 3)

-3 = x

(-3,0)

- Algebra I -
**Reiny**, Wednesday, July 21, 2010 at 10:52pmcorrect, except in your last part ...

0 = x(x + 3)

so x = 0 or x = -3

so you have 2 x intercepts, (0,0) and (-3,0)

you only had one of those.

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