Posted by Kate on .
Did I do these probelms correctly?
Find the intercepts
1. y^2 = x^2  4x
y^2 = x(x  4)
Y intercepts
y^2 = 0(0  4)
(0,0)
x intercepts
0 = x(x  4)
0 = x  4
4 = x
(4,0)
2. y = (x (x + 3))/(3x + 1)^2
y intercetps
y = (0(0 + 3))/(3(0) +1)^2
y = 3/1
(0,3)
x intercepts
0 = (x (x + 3))/(3x + 1)^2
0 = x(x + 3)
3 = x
(3,0)

Algebra I 
Reiny,
correct, except in your last part ...
0 = x(x + 3)
so x = 0 or x = 3
so you have 2 x intercepts, (0,0) and (3,0)
you only had one of those.