posted by kris- on .
two figure skaters, one weighting 625N and the other 725N,push off against each other on frictionless ice. a) if the heavest skater travels at 1.50m/s, how fast will the lighter one travel? b)how much kinetic energy is created during the skaters manauver, and where does this energy come from?
a) The net momentum will remain zero. They will leave in opposite drections.
(725/g)kg* 1.50m/s + (625/g)V = 0
V is the speed of the ligther skater. Solve for it. The acceleration of gravity (g) can be cancelled out.
V = -(725/625)*1.50 m/s
The minus sign denotes going in the opposite direction.