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July 31, 2014

July 31, 2014

Posted by **Priya** on Tuesday, July 20, 2010 at 3:12pm.

I need help setting these problems up: pleas!!

(1)Calculate the volume of 1.87 M NaI that would be needed to precipitate all of the Hg+2 ion from 199 mL of a 1.96 M Hg(NO3)2. The equation for the reaction is

2NaI (aq) + Hg(NO3)2 (aq) ---> HgI2 (2) +2NaNO3 (aq)

(2)Calculate the volume of 1.91M sulfuric acid that would be needed to neutralize 42.9 mL of a 1.24 M aqueous ammonia solution. The equation for the reaction is:

H2SO4 (aq) +2NH3 (aq) ---> 2NH4+ (aq) + SO4-2 (aq)

- CHEMISTRY -
**DrBob222**, Tuesday, July 20, 2010 at 3:28pm#1. You have the equation.

2. Convert 199 mL of 1.96 M Hg(NO3)2 to moles. moles = M x L.

3. Using the coefficients in the balanced equation, convert moles Hg(NO3)2 to moles NaI.

4. Now convert moles NaI to mL.

M = moles/L. YOu have M and moles, calculate L and convert to mL.

The second problem is done the same way.

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