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August 4, 2015

Homework Help: CHM 090

Posted by Nicole on Tuesday, July 20, 2010 at 12:19pm.

what mass of lead (II) iodide (PbI2, mass= 461 amu)is predictated by the addition of an excess of potassium iodide (KI, mass=166 amu)to 50.0 mL of 0.60 M lead(II) nitrate (Pb(NO3)2, mass=331.2 amu)?
Pb(NO3)2 + 2Kl==>PbI2 + 2KNO3

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