Posted by **M.A.** on Tuesday, July 20, 2010 at 8:49am.

The sum of the first X consecutive even numbers is 930. Find X.

10

35

30

41

Explain your solution.

- math..solve for X -
**Reiny**, Tuesday, July 20, 2010 at 10:14am
so we want

2 + 4 + 6 + ... = 930

this is an arithmetic series where

a=2 , d=2 , n = ?

n/2[2a + (n-1)d) = 930

n/2[4 + (n-1)(2)] = 930

n^2 + n - 930 = 0

(n+31)(n-30) = 0

n = 30 or n=-31, but n has to be a positive whole number.

there were 30 terms

## Answer This Question

## Related Questions

- sum - The sum of the first X consecutive even numbers is 930. Find X.
- Math - The sum of three consecutive even numbers is 36. If x represents the ...
- Algebra - Find three consecutive numbers whose sum is 930.
- math - Three consecutive even numbers have a sum between 84 and 96. a. Write an ...
- math - consecutive even integers can be represented by x,x+2,x+4 and so on. ...
- math - the sum of five consecutive numbers is 28 more than the sum of the third ...
- Math - 1.(A)(i)Show that 2+4+6+8+..+2n=n(n+1). (ii)Find the sum of the first 200...
- Algebra 2 - write an equation to solve the problem. find three consecutive even ...
- Math - When you solve questions like "The sum of 3 consecutive integers is 147. ...
- Math - the product of two consecutive positive even integers is 14 more than ...

More Related Questions