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October 1, 2014

October 1, 2014

Posted by **eng** on Tuesday, July 20, 2010 at 1:01am.

1/(1-x)=1+x+x^2+x^3...+x^n. What is need is after ....

- math -
**Reiny**, Tuesday, July 20, 2010 at 8:00amI would write it as

(1+x^4)^-1 and apply the general binomial theorem to get

= 1^-1 + (-1)(1^-2/1!(x^4) + (-1)(-2)(1^-3)/2! (x^4)^2 + (-1)(-2)(-3)(1^-3)/3! (x^4)^3 + ...

= 1 - x^4 + x^8 - x^12 + x^16 - x^20 + ...

for -1 < x < +1

I tested for x = .25 and my margin of error was 4.17x10^-10 using the above 6 terms

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