Posted by Joe on Monday, July 19, 2010 at 9:23pm.
7x^3 - 35x^2 - 6x + 30
Factor 7x^2 from the first two terms and -6 from the last two terms.
Thank you.. SO would it be
(x-5)(x+5)
7x^2(x-5)-6(x-5)...
Well, let's try your answer:
(x-5)(x+5)
= x^2 - 25. So, that doesn't work.
Doing the factoring I mentioned previously gives:
7x^2(x - 5) - 6(x - 5)
Now there are two terms. The terms have a common factor of (x-5). Using our friendly distributive law we can write:
(7x^2-6)(x-5)
Thank you so so much for your help.
Your very welcome!
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