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March 29, 2015

Posted by **Joe** on Monday, July 19, 2010 at 9:23pm.

7x^3-35x^2-6x+30

- algebra -
**Quidditch**, Monday, July 19, 2010 at 10:03pm7x^3 - 35x^2 - 6x + 30

Factor 7x^2 from the first two terms and -6 from the last two terms.

- algebra -
**Joe**, Monday, July 19, 2010 at 10:22pmThank you.. SO would it be

(x-5)(x+5)

- algebra -
**Jen**, Monday, July 19, 2010 at 10:52pm7x^2(x-5)-6(x-5)...

- algebra -
**Quidditch**, Monday, July 19, 2010 at 10:52pmWell, let's try your answer:

(x-5)(x+5)

= x^2 - 25. So, that doesn't work.

Doing the factoring I mentioned previously gives:

7x^2(x - 5) - 6(x - 5)

Now there are two terms. The terms have a common factor of (x-5). Using our friendly distributive law we can write:

(7x^2-6)(x-5)

- algebra -
**sally**, Monday, July 19, 2010 at 10:59pmThank you so so much for your help.

- algebra -
**Quidditch**, Monday, July 19, 2010 at 11:12pmYour very welcome!

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