Homework Help: Physics

Posted by Britney on Monday, July 19, 2010 at 7:25pm.

A package is dropped from a helicopter moving upward at 15 m/s. If it takes 16.0 s before the package strikes the ground, how high above the ground was the package when it was realeased?

Physics - tchrwill, Tuesday, July 20, 2010 at 10:13am
The time to V = 0 derives from Vf = Vo - gt or 0 = 15 - 9.8t yielding t(up) = 1.53sec. resulting in t(dwn) = 16 - 1.53 = 14.47 sec.

h(dwn) then derives from h = Vo(t) + g(t^2)/2 or h = 0 + 4.9t(dwn)^2 yielding h(dwn) = 4.9(14.47)^2 = 1025.96 met.

h(up) then derives from h(up) = 15(1.53) - 4.9(14.47)^2 = 11.48 met.

The vertical rise from ejection to zero vertical velocity derives from h(up) = 15(1.53) - 4.9(1.53)^2 = 11.48 met.

Therefore, the altitude of release is h(rel) = 1025.96 - 11.48 = 1014.48 met.

Answer this Question

Related Questions

physics - A passenger in a helicopter traveling upwards at 23 m/s accidentally ...
physics - A passenger in a helicopter traveling upwards at 20 m/s accidentally ...
physics - A passenger in a helicopter traveling upwards at 20 m/s accidentally ...
Physics - A helicopter is ascending vertically with a speed of 5.20 m/s. At a ...
Physics - A passenger in a helicopter traveling upwards at 17 m/s accidentally ...
Physics - A passenger in a helicopter traveling upwards at 19 m/s accidentally ...
Physics - A passenger in a helicopter traveling upwards at 18 m/s accidentally ...
high school - A passenger in a helicopter traveling upwards at 27 m/s ...
Physics - A helicopter is ascending vertically with a speed of 5.00 m/s. At a ...
physics - A helicopter is ascending vertically with a speed of 4.50 m/s. At a ...

For Further Reading

First Name:
School Subject:
Answer: