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January 31, 2015

January 31, 2015

Posted by **katrina** on Monday, July 19, 2010 at 3:58pm.

- math -
**Henry**, Monday, July 19, 2010 at 4:16pm1. Multiply both sides of Eq. by 6.

2.Subtract 2a from both sides of Eq.

3. Add 30 to each side of Eq.

4. Solve for a.

- math -
**Quidditch**, Monday, July 19, 2010 at 4:25pmFor this type of problem, try to get just the variable on one side and just the numbers on the other side.

(1/2)a - 5 = (1/3)a - 1

Add 5 to both sides to get rid of the number on the left.

(1/2)a - 5 + 5 = (1/3)a - 1 + 5

combining...

(1/2)a = (1/3)a + 4

Now subtract (1/3)a from both sides to get rid of the variable on the right side:

(1/2)a - (1/3)a = (1/3)a - (1/3)a + 4

using a common denominator of 6...

(3/6)a - (2/6)a = 4

combining...

(1/6)a = 4

multiply both sides by 6

a = 24

Substitute 24 for a in the original problem to check.

- math -
**Reiny**, Monday, July 19, 2010 at 5:34pmI know both tutors above solved the problem correctly according to the way you typed it, but I have a sneaking suspicion that you meant to type

1/(2a-5) = 1/(3a-1)

cross-multiply to get

3a - 1 = 2a - 5

a = -4

if the equation is as you typed it, then ignore my reply.

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