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1/2a-5=1/3a-1 please show me how to set this problem up and solve it

  • math - ,

    1. Multiply both sides of Eq. by 6.
    2.Subtract 2a from both sides of Eq.
    3. Add 30 to each side of Eq.
    4. Solve for a.

  • math - ,

    For this type of problem, try to get just the variable on one side and just the numbers on the other side.
    (1/2)a - 5 = (1/3)a - 1
    Add 5 to both sides to get rid of the number on the left.
    (1/2)a - 5 + 5 = (1/3)a - 1 + 5
    combining...
    (1/2)a = (1/3)a + 4
    Now subtract (1/3)a from both sides to get rid of the variable on the right side:
    (1/2)a - (1/3)a = (1/3)a - (1/3)a + 4
    using a common denominator of 6...
    (3/6)a - (2/6)a = 4
    combining...
    (1/6)a = 4
    multiply both sides by 6
    a = 24
    Substitute 24 for a in the original problem to check.

  • math - ,

    I know both tutors above solved the problem correctly according to the way you typed it, but I have a sneaking suspicion that you meant to type

    1/(2a-5) = 1/(3a-1)
    cross-multiply to get
    3a - 1 = 2a - 5
    a = -4

    if the equation is as you typed it, then ignore my reply.

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