What is the pH of 0.10 M HNO2 given Ka = 4.5x10-4.
HNO2 ==> H^+ + NO2^-
Ka = (H^+)(NO2^-)/(HNO2)
Set up an ICE chart and substitute into Ka. Solve for H^+, then convert to pH.
I got 2.17 as my final answer. Is that correct?