a ball is thrown vertically upward from the ground with the velocity of 30m/s. a) how long will it take to rise to its highest poitn? b) how high does the ball rise? c) how long after projection will the ball have a velocity of 10m/s? d) what is the total time of flight?

a ball is thrown vertically upward from the ground with the velocity of 30m/s. a) how long will it take to rise to its highest point? b) how high does the ball rise? c) how long after projection will the ball have a velocity of 10m/s upward? d)of 10 m/s downward? e) what is the displacement of the ball zero?

To give answer

a ball is thrown vertically upward from the ground with the velocity of 30m/s. a) how long will it take to rise to its highest poitn? b) how high does the ball rise? c) how long after projection will the ball have a velocity of 10m/s? d) what is the total time of flight?

From Vf = Vo - gt, 0 = 30 - 9.8t yielding t = 3.06 sec.

From h = Vo(t) - g(t^2)/2, h = 30(3.06) - 4.9(3.06)^2 yielding h = 45.88m.

From Vn = Vo - gt, 20 - 9.8t yielding t = 2.04 sec.

Since the fall time equals the rise time, the total flight time is 2(3.06) = 6.12 sec.

Fstui

To answer these questions, we can use the basic kinematic equations of motion. Let's break down each question and explain how to find the answers.

a) How long will it take to rise to its highest point?
To find the time it takes for the ball to reach its highest point, we need to consider the vertical motion. The equation that relates the initial velocity (v0), time (t), and acceleration due to gravity (g) for vertical motion is:

v = v0 - gt

Since the ball is thrown upwards, the final velocity (v) at the highest point will be zero. Rearranging the equation, we get:

0 = 30 - 9.8t

Solving this equation for t will give us the time required for the ball to reach its highest point.

b) How high does the ball rise?
To find the maximum height reached by the ball, we need to consider the displacement of the ball during its upward journey. The equation that relates displacement (d), initial velocity (v0), time (t), and acceleration due to gravity (g) for vertical motion is:

d = v0t - (1/2)gt^2

Using the time obtained from the previous question, we can substitute it into the equation to find the maximum height.

c) How long after projection will the ball have a velocity of 10 m/s?
To find the time when the ball has a velocity of 10 m/s, we need to consider the vertical motion again. Using the same equation as in question (a), we can substitute the values of initial velocity (30 m/s) and final velocity (-10 m/s), and solve for time.

d) What is the total time of flight?
The total time of flight is the sum of the time it takes for the ball to reach its highest point (question a) and the time it takes for the ball to return to the ground from its highest point. Since the ball takes the same amount of time to come back down as it took to go up, we can multiply the time obtained from question (a) by 2.

By following these explanations, you should be able to find the answers to all the questions.

How do we handle something without a symetrical rise/fall time. An object thrown vertically from a window is the basis of this question

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