Algebra
posted by Jacquie .
graph the equation x3=y (where do I plot the points?)
find the intercepts and then graph:
5x+4y=20
find the intercepts and then graph:
1.4x1.3y=3.64
graph the equation using slope and yintercept:
y=10/7x +4
graph using slope and yintercept:
x+2y=8
graph by plotting points x=2
graph x3=y
graph 5x + 4y=20
find the intercepts and graphj:
1.4x  1.3y = 3.64
graph using slope and yintercept:
y=10/7x + 4
graph using slope and yintercept:
x + 2y = 8
graph x=2 ... what plots are pointed? thought it was just 2 on the y axis but the system won't take that answer?
graph y = 2
what is the slop of x+9=y
find the slopeintercept of 9 and y intercept (0,4)
find slope intercept of 3.3 and y intercept (0,2)
find an equation of the line having given the slope and containing the given point m = 8, (2,1)
find an equation of the line having given the slope and containing the given point m=7/8, (59)
find an equation of the line given the pair of points:
(1/4, 1/3) and (3/4, 3)
what is the equation of the line?
write an equation of the line containing the given point and parallel to the given line  express answer in y=mx+b:
(7,8); x + 3y = 5
write an equation of the line containing the given point and parallel to the given line  express answer in y=mx+b:
(7, 4); 3x=5y+4
write an equation of the line containing the given point and parallel to the given line  express answer in y=mx+b:
(3,4); 9x + y =7
write an equation of the line containing the given point and perpendicular to the given line:
(2, 5); 2x + 3y = 8

Perpendicular slopes are negative reciprocals of each other (the product of one times the other is 1).
In y=mx+b m is the slope and b is the y intercept.
To find intercepts, just find (0,?) (?,0)
Parallel lines have the same slope.
Horizontal lines have a slope of zero, whereas vertical lines have no slope but that is better called an undefined slope. 0/something versus something/0.
slope= rise or fall/run
The point slope is yy1=m (xx1)
For intercept, think of the point at which something touches the respective axis. 
1. Graph X  3 = Y or Y = X  3
Let Y = 0 and solve for X: X = 3,
Let x = 0 and solve for Y: Y = 3
The points are: (0,3), (3,0).
2. 5X + 4Y = 20
Xintercept: Let Y = 0, solve for X,
X = 4.
Yintercept: Let X = 0, solve for Y.
y = 5.
3. 1.4X  1.3Y = 3.64
Xint: Let y = 0, X = 2.6, (2.6,0).
Yint: Let X = 0, Y = 2.8, (0,2.8).
4. Y = 10/7X + 4 Let X = 0, Y = 4,
(0,4), Let y = 0, X = 2.1 , (2,1 , 0)
6. X = 2. This is a vertical line 2
units to the right of Y axis. X = 2
for all values of Y: (2,0),(2,2),(2,4).
7. Y = 2.This is a horizontal line 2
units below the Xaxis. Y = 2 for all
values of X: (0,2),(2,2),(4,2).
8. X + 9 = Y or Y = X + 9, Y = mX + b,
m = coefficient of X = 1.
9. m = 9, (0,4). Y = mX + b,
Equation: Y = 9X + 4.
11. m = 8, (2,1), Y = mX + b,
1 = 8*2 + b, b = 15, Y = 8X 15.
13. (1/4,1/3),(3/4,3).
m = (3 + 1/3)/(3/4 1/4) =(10/3)/(2/4)
= 6 2/3 = 20/3, Y = (20/3)X 2.
14. (7,4), 3X = 5Y + 4. 3X 5Y = 4,
m = A/B =3/5 = 3/5 = m2, Y = mX + b
4 = 3/5*7 + b, b = 41/5 = 8 1/5.
Y = 3/5X + 41/5.
16. (2,5), 2X + 3Y = 8, m = A/B = 2/3, m2 = 3/2 = negative reciprocal of
m1. Y = mX + b, 5 = 3/2*2 + b, b=8
Y = 3/2X 8. 
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