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April 19, 2014

April 19, 2014

Posted by **Jacquie** on Sunday, July 18, 2010 at 3:54pm.

find the intercepts and then graph:

5x+4y=20

find the intercepts and then graph:

1.4x-1.3y=3.64

graph the equation using slope and y-intercept:

y=10/7x +4

graph using slope and y-intercept:

x+2y=8

graph by plotting points x=2

graph x-3=y

graph 5x + 4y=20

find the intercepts and graphj:

1.4x - 1.3y = 3.64

graph using slope and y-intercept:

y=10/7x + 4

graph using slope and y-intercept:

x + 2y = 8

graph x=2 ... what plots are pointed? thought it was just 2 on the y axis but the system won't take that answer?

graph y = -2

what is the slop of x+9=y

find the slope-intercept of 9 and y intercept (0,4)

find slope intercept of 3.3 and y intercept (0,-2)

find an equation of the line having given the slope and containing the given point m = 8, (2,1)

find an equation of the line having given the slope and containing the given point m=7/8, (5-9)

find an equation of the line given the pair of points:

(1/4, -1/3) and (3/4, 3)

what is the equation of the line?

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:

(7,8); x + 3y = 5

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:

(-7, 4); 3x=5y+4

write an equation of the line containing the given point and parallel to the given line - express answer in y=mx+b:

(3,4); 9x + y =7

write an equation of the line containing the given point and perpendicular to the given line:

(2, -5); 2x + 3y = 8

- Algebra -
**AlbertFalls**, Sunday, July 18, 2010 at 9:12pmPerpendicular slopes are negative reciprocals of each other (the product of one times the other is -1).

In y=mx+b m is the slope and b is the y intercept.

To find intercepts, just find (0,?) (?,0)

Parallel lines have the same slope.

Horizontal lines have a slope of zero, whereas vertical lines have no slope but that is better called an undefined slope. 0/something versus something/0.

slope= rise or fall/run

The point slope is y-y1=m (x-x1)

For intercept, think of the point at which something touches the respective axis.

- Algebra -
**Henry**, Sunday, July 18, 2010 at 11:49pm1. Graph X - 3 = Y or Y = X - 3

Let Y = 0 and solve for X: X = 3,

Let x = 0 and solve for Y: Y = -3

The points are: (0,-3), (3,0).

2. 5X + 4Y = 20

X-intercept: Let Y = 0, solve for X,

X = 4.

Y-intercept: Let X = 0, solve for Y.

y = 5.

3. 1.4X - 1.3Y = 3.64

X-int: Let y = 0, X = 2.6, (2.6,0).

Y-int: Let X = 0, Y = 2.8, (0,-2.8).

4. Y = 10/7X + 4 Let X = 0, Y = 4,

(0,4), Let y = 0, X = 2.1 , (2,1 , 0)

6. X = 2. This is a vertical line 2

units to the right of Y axis. X = 2

for all values of Y: (2,0),(2,2),(2,4).

7. Y = -2.This is a horizontal line 2

units below the X-axis. Y = -2 for all

values of X: (0,-2),(2,-2),(4,-2).

8. X + 9 = Y or Y = X + 9, Y = mX + b,

m = coefficient of X = 1.

9. m = 9, (0,4). Y = mX + b,

Equation: Y = 9X + 4.

11. m = 8, (2,1), Y = mX + b,

1 = 8*2 + b, b = -15, Y = 8X -15.

13. (1/4,-1/3),(3/4,3).

m = (3 + 1/3)/(3/4 -1/4) =(10/3)/(2/4)

= 6 2/3 = 20/3, Y = (20/3)X -2.

14. (-7,4), 3X = 5Y + 4. 3X -5Y = 4,

m = -A/B =-3/-5 = 3/5 = m2, Y = mX + b

4 = 3/5*-7 + b, b = 41/5 = 8 1/5.

Y = 3/5X + 41/5.

16. (2,-5), 2X + 3Y = 8, m = -A/B = -2/3, m2 = 3/2 = negative reciprocal of

m1. Y = mX + b, -5 = 3/2*2 + b, b=-8

Y = 3/2X -8.

- Algebra -
**Anonymous**, Thursday, February 21, 2013 at 1:15pm5r333333333333333333333333333

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