Posted by **Brianna ** on Sunday, July 18, 2010 at 8:45am.

You design an engine that takes in 1.5 x 10^4 J of heat at 650 K in each cycle and rejects heat at a temperature of 350 K. The engine completes 240 cycles in 1 minute. What is the theoretical maximum power output of your engine?

can you please also show what equations you use.

- Physics -
**drwls**, Sunday, July 18, 2010 at 9:55am
First get the maximum possible efficiency from the Carnot cycle formula

(Wout)/(Qin) max = 1 - (Tin/Tout)

= 1 - (350/650) = 46.2%

That efficiency applies to the work out per cycle or the average power divided by the heat transfer rate in.

You want power out, so compute the heat rate in. It is 4 cycles/s * 15,000 J = 60,000 W

Multiply that by the efficiency for the maximum power output. I get 27,692 W

Divide that by 746 W/Hp if you want horsepower.

Actual engines seldom exceed 2/3 of the Carnot efficiency, because the Carnot cycle is not practical for high speed engines.

## Answer This Question

## Related Questions

- physics - A heat engine absorbs 848 J of energy per cycle from a high-...
- thermodynamics - If a carnot engine receives heat from a heat source and ...
- science - A heat engine draws 800J of heat from its high temperature source and ...
- Physics (Heat Engines) - 21. A heat engine operates in a cycle between ...
- Physic II - a carnot heat engine operates between reservoirs at 550K and 300K, ...
- Physics - Consider an inefficient engine which draws 200 J of heat from a hot ...
- Physics - Consider an inefficient engine which draws 200 J of heat from a hot ...
- Physics - Consider an inefficient engine which draws 200 J of heat from a hot ...
- Physics - Consider an inefficient engine which draws 200 J of heat from a hot ...
- Physics - Consider an inefficient engine which draws 200 J of heat from a hot ...

More Related Questions