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April 16, 2014

April 16, 2014

Posted by **josh** on Sunday, July 18, 2010 at 6:58am.

- physics -
**drwls**, Sunday, July 18, 2010 at 7:40amA)

Solve H = (1/2) g T^2 for height, H.

T is the time to fall.

g = 9.8 m/s^2

B)

Solve M g H = (1/2) M V^2, for V.

Note that the mass M cancels out.

Therefore V = sqrt(2gH)

- physics -
**wengz**, Wednesday, February 9, 2011 at 6:15amh= 1/2 gT^2

= 1/2 (9.8)(2.5)^2

= 30.63 m/s

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