posted by Jay on .
A pendulum has a period of 1.8 s.
a) Its mass is doubled. What is its period now?
b) Its length is doubled. What is its period now?
The original pendulum is taken to a planet where g = 16 m/s2.
c) What is its period on that planet?
You should be able to figure these out yourself using the formula for the Period:
P = 2 pi*sqrt(L/g)
Note that it does not depend upon the mass of the pendulum.
really?? but how would i find L?
If you double L (the length), P increases by a factor sqrt2 = 1.414, no matter what L is.
(a) time period is independent of mass. so time period of pendulum remains same.
let initial time period be t1 when length is l and t2 be time period after double of length,i,then
from 1 and 2,
t2=root 2 times t1
where t1=1.8 s
where g=9.8m/s,ti=1.8s and g'=16m/s
solve n u will get answer