Posted by Jay on Sunday, July 18, 2010 at 12:26am.
A pendulum has a period of 1.8 s.
a) Its mass is doubled. What is its period now?
b) Its length is doubled. What is its period now?
The original pendulum is taken to a planet where g = 16 m/s2.
c) What is its period on that planet?

College Physics.  drwls, Sunday, July 18, 2010 at 1:34am
You should be able to figure these out yourself using the formula for the Period:
P = 2 pi*sqrt(L/g)
Note that it does not depend upon the mass of the pendulum.

College Physics.  Jay, Sunday, July 18, 2010 at 2:44am
really?? but how would i find L?

College Physics.  drwls, Sunday, July 18, 2010 at 6:09am
If you double L (the length), P increases by a factor sqrt2 = 1.414, no matter what L is.

College Physics.  manoj, Saturday, July 31, 2010 at 2:37am
(a) time period is independent of mass. so time period of pendulum remains same.
(b)
let initial time period be t1 when length is l and t2 be time period after double of length,i,then
t1=sqrt(l/g)....(1)
t2=sqrt(2l/g)
=root 2xsqrt(l/g)....(2)
from 1 and 2,
t2=root 2 times t1
where t1=1.8 s
(c)ti/t2=sqrt(g'/g)
where g=9.8m/s,ti=1.8s and g'=16m/s
solve n u will get answer
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